(x^2-2x+3)/(2x+1)=

Solution for (x^2-2x+3)/(2x+1)= equation:

(x^2-2x+3)/(2x+1)=

We move all terms to the left:

(x^2-2x+3)/(2x+1)-()=0


Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R


We add all the numbers together, and all the variables

(x^2-2x+3)/(2x+1)=0

We multiply all the terms by the denominator


(x^2-2x+3)=0

We get rid of parentheses

x^2-2x+3=0

a = 1; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·1·3
Δ = -8
Delta is less than zero, so there is no solution for the equation